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Proof step 14 from proof finz-bounded-03 (previous step)

m < 2 * 2^ n, ∀ m1, n. m1 < m → (m1 < 2 * 2^ n → (n = #fz(m1) ↔ m1 + 1 = 2^ n)) ⊦ n = #fz(m) ↔ m + 1 = 2^ n

User applied rule cut formula

And obtained the following new goals

Proof step 5:
even(m), m < 2 * 2^ n, ∀ m1, n. m1 < m → (m1 < 2 * 2^ n → (n = #fz(m1) ↔ m1 + 1 = 2^ n)) ⊦ n = #fz(m) ↔ m + 1 = 2^ n
Proof step 13:
m < 2 * 2^ n, ∀ m1, n. m1 < m → (m1 < 2 * 2^ n → (n = #fz(m1) ↔ m1 + 1 = 2^ n)) ⊦ even(m), n = #fz(m) ↔ m + 1 = 2^ n

Rule argument

[fma-arg: even(m)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (even(m))]]