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Proof step 13 from proof finz-bounded-05 (previous step)

n0 ≤ #fz(m) ∧ m + 1 < 2^ n0 * n + 2^ n0 ∧ n * 2^ n0 ≤ m, ∀ m1, n0, n. m1 < m → (n0 ≤ #fz(m1) ∧ m1 + 1 < 2^ n0 * n + 2^ n0 ∧ n * 2^ n0 ≤ m1 → false) ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
n * 2^ n0 ≤ m, m + 1 < 2^ n0 * n + 2^ n0, n0 ≤ #fz(m), ∀ m1, n0, n. m1 < m → (n0 ≤ #fz(m1) ∧ m1 + 1 < 2^ n0 * n + 2^ n0 ∧ n * 2^ n0 ≤ m1 → false) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m * n = n * m])]]