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Proof step 10 from proof finz-bounded (previous step)

lead(m) = 2 * m1 + 1, m + 1 = 2^ n, (2 + 2 * m) * m1 = 0, 1 + m = 2^ #fz(m), n < #fz(m) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ m0 * m = 0 ↔ m0 = 0 ∨ m = 0
Proof step 9:
lead(m) = 2 * m1 + 1, m + 1 = 2^ n, 2 + 2 * m = 0 ∨ m1 = 0, 1 + m = 2^ #fz(m), n < #fz(m) ⊦

Rule argument

[x0lemmaarg: spec-name: nat-mult instance-name: lemma-name: zero-01 antecedent: succedent: m0 * m = 0 ↔ m0 = 0 ∨ m = 0 substlist: [m, m0] → [m1, 2 + 2 * m] add preconditions?: F is rewrite lemma?: T current spec?: F rotate lemma?: F replace all?: T paths: ((0, 0, 2)) dummy: () ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (m1, 2 + 2 * m)]]