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Proof step 15 from proof split-ok (conclusion)

⊦ n + 1 = 2^ #fz(n) * lead(n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
⊦ n + 1 = lead(n) * 2 ^ #fz(n)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 2^ m = 2 ^ m])]]