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Proof step 16 from proof split-unique-2 (previous step)

2^ n * n0 = 2^ #fz(m) * lead(m), odd(n0), ∀ m1, n, n0. m1 < m → (2^ n * n0 = 2^ #fz(m1) * lead(m1) ∧ odd(n0) → n = #fz(m1) ∧ n0 = lead(m1)) ⊦ n = #fz(m) ∧ n0 = lead(m)

User applied rule cut formula

And obtained the following new goals

Proof step 6:
even(m), 2^ n * n0 = 2^ #fz(m) * lead(m), odd(n0), ∀ m1, n, n0. m1 < m → (2^ n * n0 = 2^ #fz(m1) * lead(m1) ∧ odd(n0) → n = #fz(m1) ∧ n0 = lead(m1)) ⊦ n = #fz(m) ∧ n0 = lead(m)
Proof step 15:
2^ n * n0 = 2^ #fz(m) * lead(m), odd(n0), ∀ m1, n, n0. m1 < m → (2^ n * n0 = 2^ #fz(m1) * lead(m1) ∧ odd(n0) → n = #fz(m1) ∧ n0 = lead(m1)) ⊦ even(m), n = #fz(m) ∧ n0 = lead(m)

Rule argument

[fma-arg: even(m)]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (even(m))]]