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Proof step 12 from proof split-unique (previous step)

2 * m0 + 1 = lead(m) * 2 ^ #fz(m), ∀ n0, m. n0 < m0 + m0 → (lead(n0) * 2 ^ #fz(n0) = lead(m) * 2 ^ #fz(m) → m = n0) ⊦ even(m), m = 2 * m0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
2 * m0 + 1 = lead(m) * 2 ^ #fz(m), odd(m), ∀ n0, m. n0 < m0 + m0 → (lead(n0) * 2 ^ #fz(n0) = lead(m) * 2 ^ #fz(m) → m = n0) ⊦ m = 2 * m0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ even(n) ↔ odd(n)])]]