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Proof step 16 from proof ar-elems-in-exists-h (conclusion)

⊦ n ≤ # ar ∧ a ∈ ar elems n → (∃ n0. n0 < n ∧ ar[n0] = a)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
a ∈ ar elems n, n ≤ # ar ⊦ ∃ n0. n0 < n ∧ ar[n0] = a

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]