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Proof step 19 from proof suffix-lcp (previous step)

lcp(ar, n0, n1) < lcp(ar, n0, n2), suffix(ar, n1) < suffix(ar, n2), suffix(ar, n0) < suffix(ar, n1), n2 ≤ # ar, n1 ≤ # ar, n0 ≤ # ar ⊦

User applied rule structural induction

And obtained the following new goals

Proof step 18:
∀ ar, n0, n2, n1. ¬ ( m0 = lcp(ar, n0, n2) ∧ lcp(ar, n0, n1) < lcp(ar, n0, n2) ∧ suffix(ar, n1) < suffix(ar, n2) ∧ suffix(ar, n0) < suffix(ar, n1) ∧ n2 ≤ # ar ∧ n1 ≤ # ar ∧ n0 ≤ # ar), m0 +1 = lcp(ar, n0, n2), lcp(ar, n0, n1) < lcp(ar, n0, n2), suffix(ar, n1) < suffix(ar, n2), suffix(ar, n0) < suffix(ar, n1), n2 ≤ # ar, n1 ≤ # ar, n0 ≤ # ar ⊦

Rule argument

[term-arg: lcp(ar, n0, n2)]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : nat generated by 0, +1;], [CSIMPSEQ : ⊦ m < n → n ≠ 0])]]