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Proof step 2 from proof lexicographic-irrefl (conclusion)

⊦ ¬ ar < ar

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : lexicographic, , , ⊦ ar0 < ar1 ↔ (∃ n. n ≤ # ar0 ∧ n ≤ # ar1 ∧ subarray(ar0, 0, n) = subarray(ar1, 0, n) ∧ (# ar0 = n → # ar1 > n) ∧ ( # ar0 ≠ n → # ar1 ≠ n ∧ ar0[n] < ar1[n]))], [CSIMPNAMEDSEQ : oelem, , irreflexivity, ⊦ ¬ a < a], [CSIMPNAMEDSEQ : nat, gearray, le-ls-simp, ⊦ m ≤ n → (n < m ↔ false)], [CSIMPNAMEDSEQ : nat, gearray, ax-02, ⊦ m > n ↔ n < m])]]