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Proof step 1 from proof disj-reduce (previous step)

⊦ disj(T1, T2) ↔ (∀ n, m. n < # T1 ∧ m < # T2 ∧ T1[n] ≠ empty ∧ T2[m] ≠ empty → T1[n].elem ≠ T2[m].elem)

Lemma disj