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Proof step 7 from proof hash-given (conclusion)

⊦ inv(T, h) ∧ T[h(b)] = full(a) → h(a) = h(b)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
T[h(b)] = full(a), inv(T, h) ⊦ h(a) = h(b)

Rule argument

Additional information

[Concretesimprules(())]