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Proof step 4 from proof hash-same (previous step)

T[n] = full(a), n < SIZE, inv(T, h) ⊦ h(a) = n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ inv(T, h) ↔ # T = SIZE ∧ (∀ a. h(a) < SIZE) ∧ (∀ n, a. n < # T ∧ T[n] = full(a) → h(a) = n)

Rule argument

spec: inst: name:inv seq: ⊦ inv(T, h) ↔ # T = SIZE ∧ (∀ a. h(a) < SIZE) ∧ (∀ n, a. n < # T ∧ T[n] = full(a) → h(a) = n) subst:[h, T] → [h, T] flags:rewrite, current

Additional information

[Concretesimprules(()), Extraterms((hT))]