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Proof step 11 from proof insert-correct (previous step)

T1[h1(a)] = empty, disj(T1, T0), inv(T0, h2), inv(T1, h1) ⊦ abs(T1, T0, h1, h2) ++ a = abs(T1[h1(a), full(a)], T0, h1, h2), T0[h2(a)] = full(a)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2)

Rule argument

spec:set-basic inst: name:Extension seq: ⊦ s1 = s2 ↔ (∀ a. a ∈ s1 ↔ a ∈ s2) subst:[s2, s1] → [abs(T1[h1(a), full(a)], T0, h1, h2), abs(T1, T0, h1, h2) ++ a] flags:rewrite

Additional information

[Concretesimprules(()), Extraterms((abs(T1[h1(a), full(a)], T0, h1, h2) abs(T1, T0, h1, h2) ++ a))]