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Proof step 217 from proof insert-correct (conclusion)

s = abs(T1, T2, h1, h2), inv(T1, h1), inv(T2, h2), disj(T1, T2) ⊦ [insert(a, h1, h2; T1, T2)] (s ++ a = abs(T1, T2, h1, h2) ∧ inv(T1, h1) ∧ inv(T2, h2) ∧ disj(T1, T2))

User applied rule split right

And obtained the following new goals

Proof step 216:
⟨insert(a, h1, h2; T1, T2)⟩ (T1 = T ∧ T2 = T0), s = abs(T1, T2, h1, h2), inv(T1, h1), inv(T2, h2), disj(T1, T2), s ++ a ≠ abs(T, T0, h1, h2) ∨ ¬ inv(T, h1) ∨ ¬ inv(T0, h2) ∨ ¬ disj(T, T0) ⊦

Rule argument

pos:right 1

Additional information

[Concretesimprules(())]