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Proof step 120 from proof insert-rec-correct (conclusion)

¬ a ∈ s, s = abs(T1, T2, h1, h2), inv(T1, h1), inv(T2, h2), disj(T1, T2) ⊦ [insert_rec(a, h1, h2; T1, T2)] (s ++ a = abs(T1, T2, h1, h2) ∧ inv(T1, h1) ∧ inv(T2, h2) ∧ disj(T1, T2))

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(in-abs,,, ⊦ a ∈ abs(T1, T2, h1, h2) ↔ ¬ ¬ ( T1[h1(a)] = full(a) ∨ T2[h2(a)] = full(a)))))]