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Proof step 3 from proof lookup-correct (conclusion)

s = abs(T1, T2, h1, h2) ⊦ ⟨lookup(a, T1, T2, h1, h2; found?)⟩ (found? ↔ a ∈ s)

Heuristic weak unfold applied rule call right

And obtained the following new goals

Proof step 2:
s = abs(T1, T2, h1, h2) ⊦ ⟨found?0 := T1[h1(a)] = full(a) ∨ T2[h2(a)] = full(a)⟩ (found?0 ↔ a ∈ s)

Rule argument

pos:right 1

Additional information

[Concretesimprules((Csimpdecl(lookup(a, T1, T2, h1, h2; found?) {found? := T1[h1(a)] = full(a) ∨ T2[h2(a)] = full(a) })))]