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Proof step 40 from proof dls-last (conclusion)

⊦ # x = # rx → dls(head, prev, x + a ', rx + tail0 ', next, tail) = _∃(λ r. ⌜tail0 = tail⌝ ∧ tail => mkcell(r, next, a) * dls(head, prev, x, rx, tail, r))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 39:
# x = # rx ⊦ dls(head, prev, x + a ', rx + tail0 ', next, tail) = _∃(λ r. ⌜tail0 = tail⌝ ∧ tail => mkcell(r, next, a) * dls(head, prev, x, rx, tail, r))

Rule argument

Additional information

[Concretesimprules(())]