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Proof step 7 from proof dls-one (conclusion)

⊦ dls(head, prev, a ', r ', next, tail) = (⌜head = r ∧ tail = head⌝ ∧ head => mkcell(prev, next, a))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ dls(head, prev, a ', r ', next, tail) = (⌜head = r ∧ tail = r⌝ ∧ head => mkcell(prev, next, a))

Rule argument

Additional information

[Concretesimprules(())]