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Proof step 46 from proof dls-split (conclusion)

# x0 = # rx0, # x1 = # rx1, x0 ≠ [], x1 ≠ [] ⊦ dls(head, prev, x0 + a ' + x1, rx0 + r ' + rx1, next, tail) = _∃(λ r0, r1. dls(head, prev, x0, rx0, r, r0) * r => mkcell(r0, r1, a) * dls(r1, r, x1, rx1, next, tail))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 45:
# x1 = # rx1, # x0 = # rx0 ⊦ x0 = [], x1 = [], dls(head, prev, x0 + a ' + x1, rx0 + r ' + rx1, next, tail) = _∃(λ r0, r1. dls(head, prev, x0, rx0, r, r0) * r => mkcell(r0, r1, a) * dls(r1, r, x1, rx1, next, tail))

Rule argument

Additional information

[Concretesimprules(())]