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Proof step 10 from proof remove-insert-inverse (previous step)

r ∈ rx, r ≠ head, r ≠ tail, ((dls(head, prev, x, rx, next, tail) * P))(H) ⊦ ⟪remove(r; H)⟫ ⟪insert(r; H)⟫ ((dls(head, prev, x, rx, next, tail) * P))(H)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
# x = # rx, r ≠ head, r ≠ tail, r ∈ rx, ((dls(head, prev, x, rx, next, tail) * P))(H) ⊦ ⟪remove(r; H)⟫ ⟪insert(r; H)⟫ ((dls(head, prev, x, rx, next, tail) * P))(H)

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(heap-sep,cell-heap,sep-com, ⊦ P0 * P1 = P1 * P0) Csimpnamedseq(heap-sep,cell-heap,sep-ass, ⊦ (P0 * P1) * P2 = P0 * P1 * P2) Csimpnamedforward(dllist,,dls-length, ⊦ (( dls (head, prev, x, rx, next, tail) * P) )(H) → # x = # rx)))]