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Proof step 47 from proof gcd-partial (previous step)

n = N, m = M ⊦ [: N, M | (N' = N'' ∧ M' = M''), true, true, GCD_loop(; N, M) ∥ GCD_loop(; M, N)] (gcd(n, m) = M ∧ N = gcd(n, m))

User applied rule TL right

And closed the goal!

Rule argument

args:[pos(left,right): 1, 0, 0, 4, 1, 0, args:[name: rewrite, name: gcd-loop-partial] ]

Additional information

[Concretesimprules((Csimpnamedseq(gcd-loop-partial,,, inv(n, m, N, M) ⊦ [: N, M | rely(N', M', N'', M'') , rely(M, N, M', N') , inv(n, m, N, M) , GCD_loop(; N, M) ] (N = M ∧ N = gcd(n, m)))))]