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Proof step 49 from proof gcd-partial (conclusion)

n = N, m = M ⊦ [: N, M | (N' = N'' ∧ M' = M''), true, true, GCD(; N, M)] (N = M ∧ N = gcd(n, m))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 48:
n = N, m = M ⊦ [: N, M | (N' = N'' ∧ M' = M''), true, true, GCD(; N, M)] (gcd(n, m) = M ∧ N = gcd(n, m))

Rule argument

Additional information

[Concretesimprules(())]