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Proof step 1 from proof prove-ext (conclusion)
⊦ A ≠ B ↔ ¬(A.rows = B.rows ∧ A.cols = B.cols ∧ (∀ m, n. m < A.rows ∧ n < A.cols → A[m, n] = B[m, n]))
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
A.rows = B.rows, A.cols = B.cols, ∀ m, n. m < B.rows ∧ n < B.cols → A[m, n] = B[m, n] ⊦ A = B
Rule argument
Additional information