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Proof step 68 from proof Fok-mod-cnt (previous step)

(p ' + P0)[n] = pe(m, m0, m1), Fok(F, p ' + P0, n0), n ≤ # P0, ∀ n, m, m0, m1, F, n0, m2. P0[n] = pe(m, m0, m1) ∧ n < # P0 ∧ Fok(F, P0, n0) → P0 = [] ∨ Fok(F, P0[n, pe(m, m0, m2)], n0) ⊦ Fok(F, (p ' + P0)[n, pe(m, m0, m2)], n0)

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 23:
P0 = [], (p ' + P0)[n] = pe(m, m0, m1), Fok(F, p ' + P0, n0), n ≤ # P0, ∀ n, m, m0, m1, F, n0, m2. P0[n] = pe(m, m0, m1) ∧ n < # P0 ∧ Fok(F, P0, n0) → P0 = [] ∨ Fok(F, P0[n, pe(m, m0, m2)], n0) ⊦ Fok(F, (p ' + P0)[n, pe(m, m0, m2)], n0)

Rule argument

fma:P0 = []

Additional information

[Concretesimprules(()), Extrafmas((P0 = []))]