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Proof step 5 from proof divides-XornoX-head (conclusion)
⊦ divides(p ' + P, P1, X, A1) → (¬ XornoX(p, X, A1) ↔ false)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
divides(p ' + P, P1, X, A1) ⊦ XornoX(p, X, A1)
Rule argument
Additional information
[Concretesimprules(())]