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Proof step 4 from proof elem-does-occur (previous step)

#oc(A[m], A, # A) = 0, m < # A ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 1:
⊦ m < n ∧ n ≤ # A → #oc(A[m], A, n) ≠ 0

Rule argument

spec: inst: name:elem-below-occurs seq: ⊦ m < n ∧ n ≤ # A → #oc(A[m], A, n) ≠ 0 subst:[m, n, A] → [m, # A, A] flags:current, []

Additional information

[Concretesimprules(()), Extraterms((m# AA))]