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Proof step 1 from proof nodups-oc-2 (previous step)

⊦ m < # A ∧ nodups(A) → (∀ n. (n < m → #oc(A[n], A, m) = 1) ∧ (m ≤ n ∧ n < # A → #oc(A[n], A, m) = 0))

Lemma nodups-oc