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Proof step 5 from proof nodups-oc-2 (conclusion)

⊦ m < # A ∧ nodups(A) → (∀ n. n < m → #oc(A[n], A, m) = 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
n < # A, nodups(A), m < # A, n < m, n + 1 < # A ⊦ #oc(A[n], A, m) = 1

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(nat-basic2,,succ, ⊦ m +1 = m + 1) Csimpnamedseq(nat-basic1,,f, ⊦ m < n → n ≠ 0) Csimpnamedforward(nat-basic1,,trans-1, ⊦ n < n0 ∧ n0 < n1 → n < n1) Csimpnamedforward(nat-basic1,,lf, ⊦ m < n ∧ n < n0 → m +1 < n0) Csimpnamedforward(nat-basic1,,f, ⊦ m < n → n ≠ 0)))]