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Proof step 19 from proof resetcnt-mod-cnt (conclusion)

⊦ n < # P ∧ P[n] = pe(m, m0, m1) → resetcnt(P[n, pe(m, m0, m2)]) = resetcnt(P)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
P[n] = pe(m, m0, m1), n < # P ⊦ resetcnt(P[n, pe(m, m0, m2)]) = resetcnt(P), P = []

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(list-data,partition,l, ⊦ # P = 0 ↔ P = []) Csimpnamedforward(nat-basic1,,f, ⊦ m < n → n ≠ 0)))]