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Proof step 33 from proof strengthen-recursive-edges-property (previous step)

recursive-property(φn0, φe0) ⊦ recursive-edges-property(n, φe1) ↔ recursive-edges-property (n, λ succ0, succ1, H0, H1, map0, map1. φe0(succ0, succ1, H0, H1, map0, map1) ∧ φe1(succ0, succ1, H0, H1, map0, map1))

User applied rule case distinction

And obtained the following new goals

Proof step 21:
recursive-edges-property(n, φe1), recursive-property(φn0, φe0) ⊦ recursive-edges-property (n, λ succ0, succ1, H0, H1, map0, map1. φe0(succ0, succ1, H0, H1, map0, map1) ∧ φe1(succ0, succ1, H0, H1, map0, map1))

Rule argument

pos:right 1

Additional information

[Concretesimprules(())]