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Proof step 2 from proof subset-eq (conclusion)

⊦ H ⊆ H

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ H0 ⊆ H1 ↔ (∀ r. (r ∈ H0 → r ∈ H1) ∧ (r ∈ H0 → H0[r] = H1[r]))

Rule argument

spec:heap inst:node-heap name:subset seq: ⊦ H0 ⊆ H1 ↔ (∀ r. (r ∈ H0 → r ∈ H1) ∧ (r ∈ H0 → H0[r] = H1[r])) subst:[H1, H0] → [H, H] flags:rewrite

Additional information

[Concretesimprules(()), Extraterms((HH))]