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Proof step 21 from proof eval-existing-path (previous step)

closed(H), path(x, r0, r1, H), r0 ∈ H, r1 ∈ H ⊦ ⟪eval#(r0, x, H; a?)⟫ (a? = some(H[r1].value))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 20:
closed(H), path(x, r0, r1, H), r0 ∈ H, r1 ∈ H, H[r1] = Node(a, succ) ⊦ ⟪eval#(r0, x, H; a?)⟫ (a? = some(a))

Rule argument

spec:node inst: name:elim seq: ⊦ a = nd.value ∧ succ = nd.edges ↔ nd = Node(a, succ) subst:[nd, a, succ] → [H[r1], a, succ] flags:

Additional information

[Concretesimprules((Csimpelim( ⊦ a = nd.value ∧ succ = nd.edges ↔ nd = Node(a, succ)))), Extraterms((H[r1]asucc))]