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Proof step 19 from proof eval-nonexisting-path (previous step)

∀ x0, r0, H. # x0 < # x → r0 ∈ H ∧ closed(H) ∧ (∀ r1. ¬ path(x0, r0, r1, H)) → ⟪eval#(r0, x0, H; a?)⟫ (a? = none), r0 ∈ H, closed(H), ∀ r1. ¬ path(x, r0, r1, H) ⊦ ⟪eval#(r0, x, H; a?)⟫ (a? = none)

Heuristic induction applied rule call right

And closed the goal!

Rule argument

pos:right 1

Additional information

[Concretesimprules((Csimpnamedseq(eval,,, ⊦ )))]