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Proof step 11 from proof reachable-closed (conclusion)

⊦ reachable(r0, r1, H0 ∪ H1) ∧ H0 ⊥ H1 ∧ closed(H1) ∧ r0 ∈ H1 → r1 ∈ H1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
r0 ∈ H1, closed(H1), H0 ⊥ H1, reachable(r0, r1, H0 ∪ H1) ⊦ r1 ∈ H1

Rule argument

Additional information

[Concretesimprules(())]