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Proof step 6 from proof reachable-eq (conclusion)
⊦ reachable(r, r, H) ↔ r ∈ H
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 1
:
⊦ reachable(r0, r1, H) ↔ (∃ x. path(x, r0, r1, H))
Rule argument
spec: inst: name:reachable seq: ⊦ reachable(r0, r1, H) ↔ (∃ x. path(x, r0, r1, H)) subst:[H, r1, r0] → [H, r, r] flags:rewrite, current
Additional information
[Concretesimprules(()), Extraterms((Hrr))]