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Proof step 10 from proof ascsubseq-2 (conclusion)

⊦ ascsubseq(n0 ' + n1 ', x) ↔ precedes(n0, n1, x)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec:list inst:indexseq name:One seq: ⊦ n ' = n + [] subst:[n] → [n1] flags:rewrite

Additional information

[Concretesimprules(()), Extraterms((n1))]