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Proof step 18 from proof ascsubseq-nodups (previous step)

n ∈ ix0, ascsubseq(ix0 + ix1, x), n ∈ ix1 ⊦

User applied rule structural induction

And obtained the following new goals

Proof step 17:
∀ n, ix1, x. ¬(n ∈ ix ∧ ascsubseq(ix + ix1, x) ∧ n ∈ ix1), n ∈ m + ix, ascsubseq((m + ix) + ix1, x), n ∈ ix1 ⊦

Rule argument

indvar:ix0

Additional information

[Concretesimprules((Csimpgen(ilist freely generated by [], +;) Csimpnamedseq(list,indexseq,in-empty, ⊦ ¬ n ∈ [])))]