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Proof step 4 from proof ascsubseq-prepend (previous step)

ascsubseq(n ' + ix, x) ⊦ ascsubseq(ix, x)

User applied rule structural induction

And closed the goal!

Rule argument

indvar:ix

Additional information

[Concretesimprules((Csimpnamedseq(ascsubseq-single,,, ⊦ ascsubseq(n ', x) ↔ n < # x) Csimpnamedseq(ascsubseq-base,,, ⊦ ascsubseq([], x)) Csimpnamedseq(ascsubseq-rec,,, ⊦ ascsubseq (n ' + m ' + ix, x) ↔ precedes(n, m, x) ∧ ascsubseq(m + ix, x)) Csimpgen(ilist freely generated by [], +;) Csimpnamedseq(list,indexseq,c, ⊦ n + ix = n ' + ix) Csimpnamedseq(list,indexseq,a, ⊦ (ix + ix0) + ix1 = ix + ix0 + ix1) Csimpnamedseq(list,indexseq,app, ⊦ ix + [] = ix)))]