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Proof step 7 from proof covers-ascsubseq (previous step)

covers(ixs, # x), ascsubseq(ix, x) ⊦ covers(ixs, ix)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ covers(ixs, n) ↔ (∀ n0. n0 < n → (∃ m. m < # ixs ∧ n0 ∈ ixs[m]))

Rule argument

spec: inst: name:covers-def seq: ⊦ covers(ixs, n) ↔ (∀ n0. n0 < n → (∃ m. m < # ixs ∧ n0 ∈ ixs[m])) subst:[n, ixs] → [# x, ixs] flags:rewrite, current

Additional information

[Concretesimprules(()), Extraterms((# xixs))]