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Proof step 30 from proof covers-rem (conclusion)

⊦ covers(ix ' + ixs, ix0 + n ' + ix1) ∧ ¬ covers(ixs, ix0 + ix1) → (∃ n. n ∈ ix ∧ (n ∈ ix0 ∨ n ∈ ix1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
covers(ix ' + ixs, ix0 + n ' + ix1) ⊦ covers(ixs, ix0 + ix1), ∃ n. n ∈ ix ∧ (n ∈ ix0 ∨ n ∈ ix1)

Rule argument

Additional information

[Concretesimprules(())]