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Proof step 6 from proof coversi-empty (conclusion)

⊦ covers([], ix) ↔ ix = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ covers(ixs, ix) ↔ (∀ n. n ∈ ix → (∃ m. m < # ixs ∧ n ∈ ixs[m]))

Rule argument

spec: inst: name:coversi-def seq: ⊦ covers(ixs, ix) ↔ (∀ n. n ∈ ix → (∃ m. m < # ixs ∧ n ∈ ixs[m])) subst:[ix, ixs] → [ix, []] flags:rewrite, current

Additional information

[Concretesimprules(()), Extraterms((ix[]))]