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Proof step 10 from proof inv-incbound (conclusion)

⊦ inv(ixs, n) → (¬ inv(ixs, n + m) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
inv(ixs, n) ⊦ inv(ixs, n + m)

Rule argument

Additional information

[Concretesimprules(())]