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Proof step 4 from proof inv-last-nonempty (previous step)

ixs.last = [], inv(ixs, n) ⊦ ixs = []

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 3:
∀ n. ixs0.last = [] ∧ inv(ixs0, n) → ixs0 = [], (ix + ixs0).last = [], inv(ix + ixs0, n) ⊦ ix + ixs0 = []

Rule argument

term:ixs

Additional information

[Concretesimprules((Csimpgen(illist freely generated by [], +;)))]