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Proof step 24 from proof ordered-precedes (conclusion)

⊦ ordered(ix, x) ∧ n0 ∈ ix ∧ n1 ∈ ix → (precedes(n0, n1, x) ↔ false)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
ordered(ix, x), n0 ∈ ix, n1 ∈ ix, precedes(n0, n1, x) ⊦

Rule argument

Additional information

[Concretesimprules(())]