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Proof step 8 from proof precedes-trans (
previous step
)
precedes(n, n0, x), precedes(n0, n1, x) ⊦ precedes(n, n1, x)
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 1
:
⊦ precedes(n, m, x) ↔ n < m ∧ m < # x ∧ x[n] < x[m]
Rule argument
spec: inst: name:precedes-def seq: ⊦ precedes(n, m, x) ↔ n < m ∧ m < # x ∧ x[n] < x[m] subst:[x, m, n] → [x, n0, n] flags:rewrite, current
Additional information
[Concretesimprules(()), Extraterms((xn0n))]