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Proof step 19 from proof precedesex-rev-rec1 (previous step)

precedes∃(ixs + ix0 ' + ix1 ', x) ⊦ precedes∃(ixs + ix0 ', x) ∧ (∀ n1. n1 ∈ ix1 → (∃ n0. n0 ∈ ix0 ∧ precedes(n0, n1, x)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
precedes∃(ixs + ix0 ' + ix1 ', x) ⊦ precedes∃(ixs + ix0 ', x) ∧ (n ∈ ix1 → (∃ n0. n0 ∈ ix0 ∧ precedes(n0, n, x)))

Rule argument

Additional information

[Concretesimprules(())]