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Proof step 36 from proof precedesex-rev-rec1 (conclusion)

⊦ precedes∃(ixs + ix0 ' + ix1 ', x) ↔ precedes∃(ixs + ix0, x) ∧ (∀ n1. n1 ∈ ix1 → (∃ n0. n0 ∈ ix0 ∧ precedes(n0, n1, x)))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 35:
⊦ precedes∃(ixs + ix0 ' + ix1 ', x) ↔ precedes∃(ixs + ix0 ', x) ∧ (∀ n1. n1 ∈ ix1 → (∃ n0. n0 ∈ ix0 ∧ precedes(n0, n1, x)))

Rule argument

Additional information

[Concretesimprules((Csimpnamedseq(list,indexseq-stackseq,Last, ⊦ ixs + ix = ixs + ix ')))]