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Proof step 14 from proof precedesex-solixh (conclusion)

⊦ inv(ixs, n) ∧ n ≤ # x ∧ precedes∃(ixs, x) → precedes∃(solixh(x, n, ixs), x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
precedes∃(ixs, x), n ≤ # x, inv(ixs, n) ⊦ precedes∃(solixh(x, n, ixs), x)

Rule argument

Additional information

[Concretesimprules(())]