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Proof step 14 from proof solixh-ordered (conclusion)

⊦ ordered(ixs, x) ∧ inv(ixs, n) ∧ n ≤ # x → ordered(solixh(x, n, ixs), x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
n ≤ # x, inv(ixs, n), ordered(ixs, x) ⊦ ordered(solixh(x, n, ixs), x)

Rule argument

Additional information

[Concretesimprules(())]