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Proof step 3 from proof ADD-preserves-INV (previous step)

⟪N1 := N⟫ ⟪ADD(succ(v); V, N)⟫ (N = N1 ∪ (succ(v) \ V0) ∧ V = V0 ∪ succ(v)), INV(C, N, V, n, source), v ∈ C, V0 = V ⊦ ⟪ADD(succ(v); V, N)⟫ INV(C -- v, N, V, n, source)

Heuristic symbolic execution applied rule assign left

And obtained the following new goals

Proof step 2:
⟪ADD(succ(v); V, N)⟫ (N = N0 ∪ (succ(v) \ V0) ∧ V = V0 ∪ succ(v)), INV(C, N, V, n, source), v ∈ C, V0 = V, N0 = N ⊦ ⟪ADD(succ(v); V, N)⟫ INV(C -- v, N, V, n, source)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]